What is the radius x^2+y^2+6x-2y-54=0 ?

The radius x^2+y^2+6x-2y-54=0 is r=8

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radius x^2+y^2+6x-2y-54=0

radius

x^{2} + y^{2} + 6 x - 2 y - 54 = 0

r = 8

Solution steps

x^{2} + y^{2} + 6 x - 2 y - 54 = 0

Rewrite

x^{2} + y^{2} + 6 x - 2 y - 54 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 8

And the radius is:

r = 8

(x + 3)^{2} + (y - 4)^{2} = 16

(x - 2)^{2} + (y - 5)^{2} = 106

4 x^{2} + 4 y^{2} - 12 x + 4 y - 26 = 0

4 x^{2} + 4 y^{2} + 8 x - y = 0

(x - 2)^{2} + (y - 3)^{2} = 64