What is the radius (x-2)^2+(y-3)^2=64 ?

The radius (x-2)^2+(y-3)^2=64 is r=8

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radius (x-2)^2+(y-3)^2=64

radius

(x - 2)^{2} + (y - 3)^{2} = 64

r = 8

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 64

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 64

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 8

And the radius is:

r = 8

x^{2} + (y + 2)^{2} = (20^{2})

x^{2} + y^{2} - 10 x - 8 y + 32 = 0

x^{2} + y^{2} + 6 x + 8 y + 19 = 0

x^{2} + 4 x + y^{2} - 6 y + 9 = 0

x^{2} + y^{2} - 8 x - 8 y + 28 = 0