What is the radius y^2+4x-20-2y=-x^2 ?

The radius y^2+4x-20-2y=-x^2 is r=5

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radius y^2+4x-20-2y=-x^2

radius

y^{2} + 4 x - 20 - 2 y = - x^{2}

r = 5

Solution steps

y^{2} + 4 x - 20 - 2 y = - x^{2}

Rewrite

y^{2} + 4 x - 20 - 2 y = - x^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 5

And the radius is:

r = 5

(x + 12)^{2} + (y - 9)^{2} = 35

(x - 4)^{2} + (y + 1)^{2} = 16

x^{2} + 6 x + y^{2} - 3 y = - \frac{1}{4}

x^{2} + y^{2} = 50

3 x^{2} + 3 y^{2} - 17 x = 0