What is the radius 2x^2+2y^2-9x-18y-80=0 ?

The radius 2x^2+2y^2-9x-18y-80=0 is r=(sqrt(1045))/4

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radius 2x^2+2y^2-9x-18y-80=0

radius

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

r = \frac{1045}{4}

Solution steps

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

Rewrite

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

in the form of the standard circle equation

(x - \frac{9}{4})^{2} + (y - \frac{9}{2})^{2} = (\frac{1045}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{9}{4}, \frac{9}{2}), r = \frac{1045}{4}

And the radius is:

r = \frac{1045}{4}

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x^{2} + y^{2} - x + 6 y + 9 = 0

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

x^{2} + y^{2} - 6 x + 2 y = 6

What is the radius 2x^2+2y^2-9x-18y-80=0 ?
The radius 2x^2+2y^2-9x-18y-80=0 is r=(sqrt(1045))/4