What is the radius (x+12)^2+(y-9)^2=35 ?

The radius (x+12)^2+(y-9)^2=35 is r=sqrt(35)

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radius (x+12)^2+(y-9)^2=35

radius

(x + 12)^{2} + (y - 9)^{2} = 35

r = 35

Solution steps

(x + 12)^{2} + (y - 9)^{2} = 35

Rewrite

(x + 12)^{2} + (y - 9)^{2} = 35

in the form of the standard circle equation

(x - (- 12))^{2} + (y - 9)^{2} = (35)^{2}

Therefore the circle properties are:

(a, b) = (- 12, 9), r = 35

And the radius is:

r = 35

(x - 4)^{2} + (y + 1)^{2} = 16

x^{2} + 6 x + y^{2} - 3 y = - \frac{1}{4}

x^{2} + y^{2} = 50

3 x^{2} + 3 y^{2} - 17 x = 0

x^{2} + y^{2} - 6 x + 5 = 0

What is the radius (x+12)^2+(y-9)^2=35 ?
The radius (x+12)^2+(y-9)^2=35 is r=sqrt(35)