What is the radius ((x+7)^2)/(16)+((y+5)^2)/(16)=1 ?

The radius ((x+7)^2)/(16)+((y+5)^2)/(16)=1 is r=4

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radius ((x+7)^2)/(16)+((y+5)^2)/(16)=1

radius

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

r = 4

Solution steps

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 5), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 14 x - 18 y + 81 = 0

x^{2} + y^{2} - 2 x - 16 y + 40 = 0

y^{2} + 4 x - 20 - 2 y = - x^{2}

(x + 12)^{2} + (y - 9)^{2} = 35

(x - 4)^{2} + (y + 1)^{2} = 16

What is the radius ((x+7)^2)/(16)+((y+5)^2)/(16)=1 ?
The radius ((x+7)^2)/(16)+((y+5)^2)/(16)=1 is r=4