What is the radius (x+5)^2+(y-6)^2=4 ?

The radius (x+5)^2+(y-6)^2=4 is r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius (x+5)^2+(y-6)^2=4

radius

(x + 5)^{2} + (y - 6)^{2} = 4

r = 2

Solution steps

(x + 5)^{2} + (y - 6)^{2} = 4

Rewrite

(x + 5)^{2} + (y - 6)^{2} = 4

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 6)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 5, 6), r = 2

And the radius is:

r = 2

5 x^{2} + 5 y^{2} + 10 x - 5 y + 3 = 0

x^{2} + y^{2} - 2 x - 15 = 0

x^{2} + y^{2} - 4 x + 2 y - 11 = 0

x^{2} + y^{2} - 6 x + 4 y = 7

x^{2} + y^{2} - 6 = 0