What is the radius 2(x-2)^2+2y^2=2 ?

The radius 2(x-2)^2+2y^2=2 is r=1

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radius 2(x-2)^2+2y^2=2

radius

2 (x - 2)^{2} + 2 y^{2} = 2

r = 1

Solution steps

2 (x - 2)^{2} + 2 y^{2} = 2

Rewrite

2 (x - 2)^{2} + 2 y^{2} = 2

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 1

And the radius is:

r = 1

(x - 2)^{2} + (y + 1)^{2} = 9

x^{2} + y^{2} - 4 x - 2 y - 4 = 0

x^{2} + y^{2} - 4 x + 6 y + 4 = 0

4 x^{2} + 4 y^{2} - 16 x + 4 y - 47 = 0

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27