What is the radius (x+4)^2+(y-6)^2=18 ?

The radius (x+4)^2+(y-6)^2=18 is r=sqrt(18)

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radius (x+4)^2+(y-6)^2=18

radius

(x + 4)^{2} + (y - 6)^{2} = 18

r = 18

Solution steps

(x + 4)^{2} + (y - 6)^{2} = 18

Rewrite

(x + 4)^{2} + (y - 6)^{2} = 18

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 6)^{2} = (18)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 6), r = 18

And the radius is:

r = 18

2 (x - 2)^{2} + 2 y^{2} = 2

(x - 2)^{2} + (y + 1)^{2} = 9

x^{2} + y^{2} - 4 x - 2 y - 4 = 0

x^{2} + y^{2} - 4 x + 6 y + 4 = 0

4 x^{2} + 4 y^{2} - 16 x + 4 y - 47 = 0

What is the radius (x+4)^2+(y-6)^2=18 ?
The radius (x+4)^2+(y-6)^2=18 is r=sqrt(18)