What is the radius 2x^2+2y^2+4x-30=0 ?

The radius 2x^2+2y^2+4x-30=0 is r=4

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radius 2x^2+2y^2+4x-30=0

radius

2 x^{2} + 2 y^{2} + 4 x - 30 = 0

r = 4

Solution steps

2 x^{2} + 2 y^{2} + 4 x - 30 = 0

Rewrite

2 x^{2} + 2 y^{2} + 4 x - 30 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 4

And the radius is:

r = 4

x^{2} + (y - 3)^{2} = 2.6

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

(x - 1)^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} - 6 x + 8 y = 144