What is the radius 8x^2+8y^2-20x+64y-371=0 ?

The radius 8x^2+8y^2-20x+64y-371=0 is r=(sqrt(1023))/4

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radius 8x^2+8y^2-20x+64y-371=0

radius

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

r = \frac{1023}{4}

Solution steps

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

Rewrite

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

in the form of the standard circle equation

(x - \frac{5}{4})^{2} + (y - (- 4))^{2} = (\frac{1023}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{4}, - 4), r = \frac{1023}{4}

And the radius is:

r = \frac{1023}{4}

x^{2} + y^{2} + 4 y - 60 = 0

x^{2} + y^{2} = 200

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

x^{2} + y^{2} - 4 x + 8 y = 16

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0

What is the radius 8x^2+8y^2-20x+64y-371=0 ?
The radius 8x^2+8y^2-20x+64y-371=0 is r=(sqrt(1023))/4