What is the radius x^2+10x+y^2-16y-11=0 ?

The radius x^2+10x+y^2-16y-11=0 is r=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+10x+y^2-16y-11=0

radius

x^{2} + 10 x + y^{2} - 16 y - 11 = 0

r = 10

Solution steps

x^{2} + 10 x + y^{2} - 16 y - 11 = 0

Rewrite

x^{2} + 10 x + y^{2} - 16 y - 11 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 8)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 5, 8), r = 10

And the radius is:

r = 10

x^{2} - 6 x + y^{2} + 8 y - 24 = 0

x^{2} + 24 x + y^{2} + 10 y = - 160

x^{2} + y^{2} - 6 x = 7

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

x^{2} + y^{2} + 4 x - 6 y - 23 = 0

What is the radius x^2+10x+y^2-16y-11=0 ?
The radius x^2+10x+y^2-16y-11=0 is r=10