What is the radius x^2+24x+y^2+10y=-160 ?

The radius x^2+24x+y^2+10y=-160 is r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+24x+y^2+10y=-160

radius

x^{2} + 24 x + y^{2} + 10 y = - 160

r = 3

Solution steps

x^{2} + 24 x + y^{2} + 10 y = - 160

Rewrite

x^{2} + 24 x + y^{2} + 10 y = - 160

in the form of the standard circle equation

(x - (- 12))^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 12, - 5), r = 3

And the radius is:

r = 3

x^{2} + y^{2} - 6 x = 7

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

x^{2} + y^{2} + 4 x - 6 y - 23 = 0

x^{2} + y^{2} - 2 y = 15

x^{2} + (y - 4)^{2} = 25

What is the radius x^2+24x+y^2+10y=-160 ?
The radius x^2+24x+y^2+10y=-160 is r=3