What is the radius x^2+y^2-6x+4y+4=0 ?

The radius x^2+y^2-6x+4y+4=0 is r=3

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radius x^2+y^2-6x+4y+4=0

radius

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

r = 3

Solution steps

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

Rewrite

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 3

And the radius is:

r = 3

x^{2} + y^{2} + 4 x - 6 y - 23 = 0

x^{2} + y^{2} - 2 y = 15

x^{2} + (y - 4)^{2} = 25

x^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 16 = 0