What is x^2+z^2+4x-6z+9=0 ?

The solution to x^2+z^2+4x-6z+9=0 is Circle with (a,b)=(-2,3),r=2

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x^2+z^2+4x-6z+9=0

x^{2} + z^{2} + 4 x - 6 z + 9 = 0

(a, b) = (- 2, 3), r = 2

Solution steps

x^{2} + z^{2} + 4 x - 6 z + 9 = 0

Rewrite

x^{2} + z^{2} + 4 x - 6 z + 9 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (z - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 2

(x - 6)^{2} + y^{2} = 1

(x - 7)^{2} + (y + 3)^{2} = 9

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

x^{2} + y^{2} + 12 x + 9 y - 18 = 0

(x + 14)^{2} + y^{2} = 144

What is x^2+z^2+4x-6z+9=0 ?
The solution to x^2+z^2+4x-6z+9=0 is Circle with (a,b)=(-2,3),r=2