What is (x+0.738)^2+(y+1.119)^2=6.996^2 ?

The solution to (x+0.738)^2+(y+1.119)^2=6.996^2 is Circle with (a,b)=(-0.738,-1.119),r=6.996

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(x+0.738)^2+(y+1.119)^2=6.996^2

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

(a, b) = (- 0.738, - 1.119), r = 6.996

Solution steps

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

Rewrite

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

in the form of the standard circle equation

(x - (- 0.738))^{2} + (y - (- 1.119))^{2} = 6.99 6^{2}

Therefore the circle properties are:

(a, b) = (- 0.738, - 1.119), r = 6.996

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What is (x+0.738)^2+(y+1.119)^2=6.996^2 ?
The solution to (x+0.738)^2+(y+1.119)^2=6.996^2 is Circle with (a,b)=(-0.738,-1.119),r=6.996