What is (x-7)^2+(y+3)^2=9 ?

The solution to (x-7)^2+(y+3)^2=9 is Circle with (a,b)=(7,-3),r=3

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(x-7)^2+(y+3)^2=9

(x - 7)^{2} + (y + 3)^{2} = 9

(a, b) = (7, - 3), r = 3

Solution steps

(x - 7)^{2} + (y + 3)^{2} = 9

Rewrite

(x - 7)^{2} + (y + 3)^{2} = 9

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (7, - 3), r = 3

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

x^{2} + y^{2} + 12 x + 9 y - 18 = 0

(x + 14)^{2} + y^{2} = 144

x^{2} + y^{2} - 8 x - 4 y + 5 = 0

x^{2} + 2 x + y^{2} + 2 y = - 1

What is (x-7)^2+(y+3)^2=9 ?
The solution to (x-7)^2+(y+3)^2=9 is Circle with (a,b)=(7,-3),r=3