What is (y^2)/2 =-(x^2)/2+2 ?

The solution to (y^2)/2 =-(x^2)/2+2 is Circle with (a,b)=(0,0),r=2

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(y^2)/2 =-(x^2)/2+2

\frac{y ^{2}}{2} = - \frac{x ^{2}}{2} + 2

(a, b) = (0, 0), r = 2

Solution steps

\frac{y ^{2}}{2} = - \frac{x ^{2}}{2} + 2

Rewrite

\frac{y ^{2}}{2} = - \frac{x ^{2}}{2} + 2

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

x^{2} + y^{2} + 10 x - 56 = 0

(x + 5)^{2} + (y + 2)^{2} = 21

0 = 3 - 6 (x^{2} + y^{2})

x^{2} + y^{2} + (- x^{2} + y^{2})^{2} = 9

(x - 3)^{2} + (y + 5)^{2} = 100

What is (y^2)/2 =-(x^2)/2+2 ?
The solution to (y^2)/2 =-(x^2)/2+2 is Circle with (a,b)=(0,0),r=2