What is x^2+y^2+10x-56=0 ?

The solution to x^2+y^2+10x-56=0 is Circle with (a,b)=(-5,0),r=9

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x^2+y^2+10x-56=0

x^{2} + y^{2} + 10 x - 56 = 0

(a, b) = (- 5, 0), r = 9

Solution steps

x^{2} + y^{2} + 10 x - 56 = 0

Rewrite

x^{2} + y^{2} + 10 x - 56 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 0)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 5, 0), r = 9

(x + 5)^{2} + (y + 2)^{2} = 21

0 = 3 - 6 (x^{2} + y^{2})

x^{2} + y^{2} + (- x^{2} + y^{2})^{2} = 9

(x - 3)^{2} + (y + 5)^{2} = 100

π x^{(2)} + π y^{(2)} + 8 x - 10 π y - 400 = 0

What is x^2+y^2+10x-56=0 ?
The solution to x^2+y^2+10x-56=0 is Circle with (a,b)=(-5,0),r=9