What is 5x^2+5y^2+10x-y=10 ?

The solution to 5x^2+5y^2+10x-y=10 is Circle with (a,b)=(-1, 1/10),r=(sqrt(301))/(10)

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5x^2+5y^2+10x-y=10

5 x^{2} + 5 y^{2} + 10 x - y = 10

(a, b) = (- 1, \frac{1}{10}), r = \frac{301}{10}

Solution steps

5 x^{2} + 5 y^{2} + 10 x - y = 10

Rewrite

5 x^{2} + 5 y^{2} + 10 x - y = 10

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{1}{10})^{2} = (\frac{301}{10})^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{1}{10}), r = \frac{301}{10}

x^{2} + (y - 1)^{2} - 5 \leq 0

(x + 3)^{2} + (y + 5)^{2} = 5

(x + 3)^{2} + (y + 5)^{2} = 3

3 = - 6 x + 4 y + x^{2} + y^{2}

(x + 2)^{2} + (y + 9)^{2} = 70

What is 5x^2+5y^2+10x-y=10 ?
The solution to 5x^2+5y^2+10x-y=10 is Circle with (a,b)=(-1, 1/10),r=(sqrt(301))/(10)