What is (x-3)^2+(y-5)^2=25 ?

The solution to (x-3)^2+(y-5)^2=25 is Circle with (a,b)=(3,5),r=5

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(x-3)^2+(y-5)^2=25

(x - 3)^{2} + (y - 5)^{2} = 25

(a, b) = (3, 5), r = 5

Solution steps

(x - 3)^{2} + (y - 5)^{2} = 25

Rewrite

(x - 3)^{2} + (y - 5)^{2} = 25

in the form of the standard circle equation

(x - 3)^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, 5), r = 5

x^{2} + y^{2} + 10 x - 16 y + 64 = 0

2 (x^{2} - 3) + 2 (y^{2} - 1) = 45

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)

(x + 2)^{2} + (y + 1)^{2} = 2

x^{2} + 4 x + y^{2} + 10 y = - 20

What is (x-3)^2+(y-5)^2=25 ?
The solution to (x-3)^2+(y-5)^2=25 is Circle with (a,b)=(3,5),r=5