What is x^2+y^2+10x+6y-47=0 ?

The solution to x^2+y^2+10x+6y-47=0 is Circle with (a,b)=(-5,-3),r=9

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x^2+y^2+10x+6y-47=0

x^{2} + y^{2} + 10 x + 6 y - 47 = 0

(a, b) = (- 5, - 3), r = 9

Solution steps

x^{2} + y^{2} + 10 x + 6 y - 47 = 0

Rewrite

x^{2} + y^{2} + 10 x + 6 y - 47 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 3))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 3), r = 9

x^{2} + y^{2} - 5 x = 3

(x - 1 + 23)^{2} + (y - 3)^{2} = 20

x^{2} + y^{2} + 4 x + 2 y - 27 = 0

x^{2} + y^{2} = - 4 x - 3 y

(x - (- 4))^{2} + (y - (9))^{2} = 3^{2}

What is x^2+y^2+10x+6y-47=0 ?
The solution to x^2+y^2+10x+6y-47=0 is Circle with (a,b)=(-5,-3),r=9