What is x^2+y^2=-4x-3y ?

The solution to x^2+y^2=-4x-3y is Circle with (a,b)=(-2,-3/2),r= 5/2

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x^2+y^2=-4x-3y

x^{2} + y^{2} = - 4 x - 3 y

(a, b) = (- 2, - \frac{3}{2}), r = \frac{5}{2}

Solution steps

x^{2} + y^{2} = - 4 x - 3 y

Rewrite

x^{2} + y^{2} = - 4 x - 3 y

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- \frac{3}{2}))^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 2, - \frac{3}{2}), r = \frac{5}{2}

(x - (- 4))^{2} + (y - (9))^{2} = 3^{2}

x^{2} + (y + 4)^{2} = 25

(x^{2} + 2 x + 1) + (y^{2} - 6 y + 9) = - 7 + 1 + 9

4 x^{(2)} + 40 x + 4 y^{(2)} - 32 y = 5

x^{2} + y^{2} - 10 x + 2 y + 20 = 0

What is x^2+y^2=-4x-3y ?
The solution to x^2+y^2=-4x-3y is Circle with (a,b)=(-2,-3/2),r= 5/2