What is x^2+y^2+10x-16y+64=0 ?

The solution to x^2+y^2+10x-16y+64=0 is Circle with (a,b)=(-5,8),r=5

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x^2+y^2+10x-16y+64=0

x^{2} + y^{2} + 10 x - 16 y + 64 = 0

(a, b) = (- 5, 8), r = 5

Solution steps

x^{2} + y^{2} + 10 x - 16 y + 64 = 0

Rewrite

x^{2} + y^{2} + 10 x - 16 y + 64 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 8)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 5, 8), r = 5

2 (x^{2} - 3) + 2 (y^{2} - 1) = 45

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)

(x + 2)^{2} + (y + 1)^{2} = 2

x^{2} + 4 x + y^{2} + 10 y = - 20

x^{2} + y^{2} + 10 x + 6 y - 47 = 0

What is x^2+y^2+10x-16y+64=0 ?
The solution to x^2+y^2+10x-16y+64=0 is Circle with (a,b)=(-5,8),r=5