What is 364+28y+y^2+x^2=-26x ?

The solution to 364+28y+y^2+x^2=-26x is Circle with (a,b)=(-13,-14),r=1

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364+28y+y^2+x^2=-26x

364 + 28 y + y^{2} + x^{2} = - 26 x

(a, b) = (- 13, - 14), r = 1

Solution steps

364 + 28 y + y^{2} + x^{2} = - 26 x

Rewrite

364 + 28 y + y^{2} + x^{2} = - 26 x

in the form of the standard circle equation

(x - (- 13))^{2} + (y - (- 14))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 13, - 14), r = 1

x^{2} + y^{2} - 49 < 0

x^{2} + y^{2} + 6 x - 9 y = 6

(x + 3)^{2} + y^{2} = 5

x^{2} + y^{2} - 7 x = 39 - 2 y

x^{2} + y^{2} - 10 x - 4 y + 13 = 0

What is 364+28y+y^2+x^2=-26x ?
The solution to 364+28y+y^2+x^2=-26x is Circle with (a,b)=(-13,-14),r=1