What is x^2+y^2+6x-9y=6 ?

The solution to x^2+y^2+6x-9y=6 is Circle with (a,b)=(-3, 9/2),r=(sqrt(141))/2

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x^2+y^2+6x-9y=6

x^{2} + y^{2} + 6 x - 9 y = 6

(a, b) = (- 3, \frac{9}{2}), r = \frac{141}{2}

Solution steps

x^{2} + y^{2} + 6 x - 9 y = 6

Rewrite

x^{2} + y^{2} + 6 x - 9 y = 6

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{9}{2})^{2} = (\frac{141}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{9}{2}), r = \frac{141}{2}

(x + 3)^{2} + y^{2} = 5

x^{2} + y^{2} - 7 x = 39 - 2 y

x^{2} + y^{2} - 10 x - 4 y + 13 = 0

(x - 3)^{2} + (y + 1)^{2} = 64

(x + 9)^{2} + (y - 4)^{2} = \frac{32}{4}

What is x^2+y^2+6x-9y=6 ?
The solution to x^2+y^2+6x-9y=6 is Circle with (a,b)=(-3, 9/2),r=(sqrt(141))/2