What is x^2+y^2-7x=39-2y ?

The solution to x^2+y^2-7x=39-2y is Circle with (a,b)=(7/2 ,-1),r=(sqrt(209))/2

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x^2+y^2-7x=39-2y

x^{2} + y^{2} - 7 x = 39 - 2 y

(a, b) = (\frac{7}{2}, - 1), r = \frac{209}{2}

Solution steps

x^{2} + y^{2} - 7 x = 39 - 2 y

Rewrite

x^{2} + y^{2} - 7 x = 39 - 2 y

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- 1))^{2} = (\frac{209}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - 1), r = \frac{209}{2}

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9 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

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What is x^2+y^2-7x=39-2y ?
The solution to x^2+y^2-7x=39-2y is Circle with (a,b)=(7/2 ,-1),r=(sqrt(209))/2