What is the inverse of f(x)=(1-2x)^2+5 ?

The inverse of f(x)=(1-2x)^2+5 is -(sqrt(x-5)-1)/2 ,-(-sqrt(x-5)-1)/2

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inverse of f(x)=(1-2x)^2+5

inverse

f (x) = (1 - 2 x)^{2} + 5

- \frac{x - 5 - 1}{2}, - \frac{- x - 5 - 1}{2}

Solution steps

y = (1 - 2 x)^{2} + 5

Replace

x

with

y

x = (1 - 2 y)^{2} + 5

Solve for

y, x = (1 - 2 y)^{2} + 5

- \frac{x - 5 - 1}{2}, - \frac{- x - 5 - 1}{2}

x^{\frac{1}{2}}

x^{2} + 4 x - 5

f (x) = 11.6 - 4 x

f (x) = 3 x^{2} - 10 x + 3

f (x) = \frac{x + 3}{x - 4}

What is the inverse of f(x)=(1-2x)^2+5 ?
The inverse of f(x)=(1-2x)^2+5 is -(sqrt(x-5)-1)/2 ,-(-sqrt(x-5)-1)/2