What is the domain of f(x)=(sqrt(x+3))/(x-4) ?

The domain of f(x)=(sqrt(x+3))/(x-4) is -3 4

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domain of f(x)=(sqrt(x+3))/(x-4)

domain

f (x) = \frac{x + 3}{x - 4}

- 3 \leq x < 4 or x > 4

Interval Notation

[- 3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 3 \leq x < 4 or x > 4

f (x) = \frac{x ^{2} + 2 x}{x ^{2} - 2 x}

tan (2 θ - \frac{11 π}{6}) - 1

f (x) = - x^{2} - 6 x

f (x) = \frac{x ^{2} + 3 x}{x ^{2} + x - 6}

(- 2, - 1), (3, 2)

What is the domain of f(x)=(sqrt(x+3))/(x-4) ?
The domain of f(x)=(sqrt(x+3))/(x-4) is -3<= x<4\lor x>4