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Popular >

range of x^2+4x-5

Solution

range

x^{2} + 4 x - 5

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

x^{2} + 4 x - 5 :

Minimum

(- 2, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 2, - 9)

f (x) \geq - 9

Popular Examples

inverse of f(x)=11.6-4x inverse

f (x) = 11.6 - 4 x

extreme f(x)=3x^2-10x+3 extreme points

f (x) = 3 x^{2} - 10 x + 3

domain of f(x)=(sqrt(x+3))/(x-4)domain

f (x) = \frac{x + 3}{x - 4}

asymptotes of f(x)=(x^2+2x)/(x^2-2x)asymptotes

f (x) = \frac{x ^{2} + 2 x}{x ^{2} - 2 x}

domain of tan(2θ-(11pi)/6)-1 domain

tan (2 θ - \frac{11 π}{6}) - 1

Frequently Asked Questions (FAQ)

What is the range of x^2+4x-5 ?
The range of x^2+4x-5 is f(x)>=-9