extreme f(x)=4-3x-x^2

Lösung

extrempunkte

f (x) = 4 - 3 x - x^{2}

Maximum (- \frac{3}{2}, \frac{25}{4})

Schritte zur Lösung

f^{'} (x) = - 2 x - 3

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{3}{2},

Absteigend

: - \frac{3}{2} < x < \infty

Stecke

x = - \frac{3}{2}

4 - 3 x - x^{2} : \frac{25}{4}

Maximum (- \frac{3}{2}, \frac{25}{4})

e x t re m e f (x) = f (x) = x^{3} - 9 x^{2} + 15 x + 4

e x t re m e f (x) = \frac{x ^{2} + 81}{4 x}, 1 \leq x \leq 12

e x t re m e f (x, y) = 1 + x^{2} - y^{2}

e x t re m e f (x, y) = 2 x^{2} + 3 x y + 4 y^{2} - 5 x + 2

e x t re m e f (x) = x e^{- \frac{x ^{2}}{32}} [- 3.8]