derivative of sqrt(2x+2)

Lösung

\frac{d}{d x} (2 x + 2)

\frac{1}{2 x + 2}

Schritte zur Lösung

\frac{d}{d x} (2 x + 2)

Wende die Kettenregel an:

\frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

= \frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

\frac{d}{d x} (2 x + 2) = 2

= \frac{1}{2 2 x + 2} \cdot 2

Vereinfache

\frac{1}{2 2 x + 2} \cdot 2 : \frac{1}{2 x + 2}

= \frac{1}{2 x + 2}

\int \frac{x}{e ^{- 2 x}} d x

\int \frac{1}{u ^{2} + 2} d u

\int_{0}^{1} e^{s} sin (t - s) d s

t an g e n t f (x) = x^{3} - 9 x, at x = (- 3)

t an g e n t f (x) = 2 x - \frac{1}{x}, at x = 0.5