integral of x/(e^{-2x)}

Lösung

\int \frac{x}{e ^{- 2 x}} d x

\frac{1}{2} e^{2 x} x - \frac{1}{4} e^{2 x} + C

Schritte zur Lösung

\int \frac{x}{e ^{- 2 x}} d x

Wende die partielle Integration an

= \frac{1}{2} e^{2 x} x - \int \frac{1}{2} e^{2 x} d x

\int \frac{1}{2} e^{2 x} d x = \frac{1}{4} e^{2 x}

= \frac{1}{2} e^{2 x} x - \frac{1}{4} e^{2 x}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} e^{2 x} x - \frac{1}{4} e^{2 x} + C

\int \frac{1}{u ^{2} + 2} d u

\int_{0}^{1} e^{s} sin (t - s) d s

t an g e n t f (x) = x^{3} - 9 x, at x = (- 3)

t an g e n t f (x) = 2 x - \frac{1}{x}, at x = 0.5

x \to 1 + lim (\frac{5}{x - 1})