y^{''}+2y^'-3y=0,y(0)=4,y^'(0)=1

Lösung

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 4, y^{^{'}} (0) = 1

y = (4 - \frac{3}{4}) e^{t} + \frac{3}{4} e^{- 3 t}

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = (4 - \frac{3}{4}) e^{t} + \frac{3}{4} e^{- 3 t}

y = (4 - \frac{3}{4}) e^{t} + \frac{3}{4} e^{- 3 t}

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