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人気のある微分積分 >

integral from 1/2 to 1 of sin(2pi)x

解

\int_{\frac{1}{2}}^{1} sin (2 π) x d x

解

0

解答ステップ

\int_{\frac{1}{2}}^{1} sin (2 π) x d x

sin (2 π) x = 0

= \int_{\frac{1}{2}}^{1} 0 d x

定数の積分:

\int a d x = a x

= [0 \cdot x]_{\frac{1}{2}}^{1}

簡素化

= [0]_{\frac{1}{2}}^{1}

限度を計算する:

0

= 0

グラフ

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