integral from 1/2 to 1 of sin(2pi)x

Lösung

\int_{\frac{1}{2}}^{1} sin (2 π) x d x

0

Schritte zur Lösung

\int_{\frac{1}{2}}^{1} sin (2 π) x d x

sin (2 π) x = 0

= \int_{\frac{1}{2}}^{1} 0 d x

Integral einer Konstanten :

\int a d x = a x

= [0 \cdot x]_{\frac{1}{2}}^{1}

Vereinfache

= [0]_{\frac{1}{2}}^{1}

Berechne die Grenzen:

0

= 0

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