integral from 1 to e^2 of xln(x)

Lösung

\int_{1}^{e^{2}} x ln (x) d x

\frac{3 e ^{4} + 1}{4}

Dezimale

41.19861 \dots

Schritte zur Lösung

\int_{1}^{e^{2}} x ln (x) d x

Wende die partielle Integration an

= [\frac{1}{2} (x^{2} ln (x) - 2 \cdot \int \frac{x}{2} d x)]_{1}^{e^{2}}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= [\frac{1}{2} (x^{2} ln (x) - 2 \cdot \frac{x ^{2}}{4})]_{1}^{e^{2}}

2 \cdot \frac{x ^{2}}{4} = \frac{x ^{2}}{2}

= [\frac{1}{2} (x^{2} ln (x) - \frac{x ^{2}}{2})]_{1}^{e^{2}}

Berechne die Grenzen:

\frac{3 e ^{4}}{4} + \frac{1}{4}

= \frac{3 e ^{4}}{4} + \frac{1}{4}

Vereinfache

= \frac{3 e ^{4} + 1}{4}

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