What is the d/(dt)(Ate^t) ?

The d/(dt)(Ate^t) is A(e^t+e^tt)

What is the first d/(dt)(Ate^t) ?

The first d/(dt)(Ate^t) is A(e^t+e^tt)

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\frac{d}{d t} (A t e^{t})

A (e^{t} + e^{t} t)

Solution steps

\frac{d}{d t} (A t e^{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= A \frac{d}{d t} (t e^{t})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = e^{t}

= A (\frac{d t}{d t} e^{t} + \frac{d}{d t} (e^{t}) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (e^{t}) = e^{t}

= A (1 \cdot e^{t} + e^{t} t)

Simplify

= A (e^{t} + e^{t} t)

n = 1 \sum \infty \frac{n}{1 - 7 n}

\frac{d}{d x} (\frac{- 6 x}{2 x - 1})

\frac{4 x ^{5} + 7}{x ^{3}}

\frac{d}{d x} (ln (\frac{x ^{2} + 1}{x + 4}))

y^{^{''}} + 3 y^{^{'}} + 2 y = 0, y (0) = 2, y (1) = 3