What is the derivative of (4x^5+7)/(x^3) ?

The derivative of (4x^5+7)/(x^3) is (8x^5-21)/(x^4)

What is the first derivative of (4x^5+7)/(x^3) ?

The first derivative of (4x^5+7)/(x^3) is (8x^5-21)/(x^4)

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derivative of

\frac{4 x ^{5} + 7}{x ^{3}}

\frac{8 x ^{5} - 21}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{4 x ^{5} + 7}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{5} + 7 ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ( 4 x ^{5} + 7 )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (4 x^{5} + 7) = 20 x^{4}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{20 x ^{4} x ^{3} - 3 x ^{2} ( 4 x ^{5} + 7 )}{( x ^{3} ) ^{2}}

Simplify

\frac{20 x ^{4} x ^{3} - 3 x ^{2} ( 4 x ^{5} + 7 )}{( x ^{3} ) ^{2}} : \frac{8 x ^{5} - 21}{x ^{4}}

= \frac{8 x ^{5} - 21}{x ^{4}}

\frac{d}{d x} (ln (\frac{x ^{2} + 1}{x + 4}))

y^{^{''}} + 3 y^{^{'}} + 2 y = 0, y (0) = 2, y (1) = 3

x \to 7 + lim (ln (x - 7))

\int e^{7 x + 9} d x

\int \frac{sin ( x )}{2 - cos ^{2} ( x )} d x

What is the derivative of (4x^5+7)/(x^3) ?
The derivative of (4x^5+7)/(x^3) is (8x^5-21)/(x^4)
What is the first derivative of (4x^5+7)/(x^3) ?
The first derivative of (4x^5+7)/(x^3) is (8x^5-21)/(x^4)