derivative of e^{x^2-x+1}

Lösung

\frac{d}{d x} (e^{x^{2} - x + 1})

e^{x^{2} - x + 1} (2 x - 1)

Schritte zur Lösung

\frac{d}{d x} (e^{x^{2} - x + 1})

Wende die Kettenregel an:

e^{x^{2} - x + 1} \frac{d}{d x} (x^{2} - x + 1)

= e^{x^{2} - x + 1} \frac{d}{d x} (x^{2} - x + 1)

\frac{d}{d x} (x^{2} - x + 1) = 2 x - 1

= e^{x^{2} - x + 1} (2 x - 1)

\frac{d}{d x} (x^{4} + 4 x^{3} - 2 x^{2} - 12 x)

\frac{d}{d x} (1 0^{- 2 x})

\int \frac{x ^{2}}{2 x - 1} d x

in v erse l a pl a ce \frac{8}{( 9 s ^{2} + 12 s + 4 ) ( s )}

\int x \cdot e^{x^{2}} d x