What is the integral from-infinity to 0 of 1/(3-7x) ?

The integral from-infinity to 0 of 1/(3-7x) is diverges

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integral from-infinity to 0 of 1/(3-7x)

\int_{- \infty}^{0} \frac{1}{3 - 7 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{3 - 7 x} d x

Compute the indefinite integral:

\int \frac{1}{3 - 7 x} d x = - \frac{1}{7} ln ∣ 3 - 7 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{3 - 7 x} d x =

diverges

= diverges

\int sin (2 x) sin (x) d x

\int sec (x) - tan (x) d x

\frac{8.2}{4.2 x ^{2} + 4 x + 5}

\frac{s ^{2}}{( s ^{2} - 1 ) ^{2}}

\frac{10}{x ^{2}}

What is the integral from-infinity to 0 of 1/(3-7x) ?
The integral from-infinity to 0 of 1/(3-7x) is diverges