What is the integral of sin(2x)sin(x) ?

The integral of sin(2x)sin(x) is 2/3 sin^3(x)+C

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integral of sin(2x)sin(x)

\int sin (2 x) sin (x) d x

\frac{2}{3} sin^{3} (x) + C

Solution steps

\int sin (2 x) sin (x) d x

Rewrite using trig identities

= \int 2 sin^{2} (x) cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin^{2} (x) cos (x) d x

Apply u-substitution

: \int u^{2} d u

= 2 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 2 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= 2 \cdot \frac{sin ^{3} ( x )}{3}

Simplify

2 \cdot \frac{sin ^{3} ( x )}{3} : \frac{2}{3} sin^{3} (x)

= \frac{2}{3} sin^{3} (x)

Add a constant to the solution

= \frac{2}{3} sin^{3} (x) + C

\int sec (x) - tan (x) d x

\frac{8.2}{4.2 x ^{2} + 4 x + 5}

\frac{s ^{2}}{( s ^{2} - 1 ) ^{2}}

\frac{10}{x ^{2}}

n = 0 \sum \infty \frac{6}{n ( n + 3 )}

What is the integral of sin(2x)sin(x) ?
The integral of sin(2x)sin(x) is 2/3 sin^3(x)+C