What is the derivative of y=sin(x)-cos(x) ?

The derivative of y=sin(x)-cos(x) is cos(x)+sin(x)

What is the first derivative of y=sin(x)-cos(x) ?

The first derivative of y=sin(x)-cos(x) is cos(x)+sin(x)

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derivative of

y = sin (x) - cos (x)

cos (x) + sin (x)

Solution steps

\frac{d}{d x} (sin (x) - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (cos (x)) = - sin (x)

= cos (x) - (- sin (x))

Simplify

= cos (x) + sin (x)

\int \frac{1}{( 1 - x ^{2} )} d x

y^{^{'}} + 3 y = x e^{- 2 x} + e^{- 3 x}

y^{^{''}} = x (y^{^{'}})^{2}

\frac{x}{1 + x ^{2}}, at x = 0

\int 36 x e^{- 9 x} d x

What is the derivative of y=sin(x)-cos(x) ?
The derivative of y=sin(x)-cos(x) is cos(x)+sin(x)
What is the first derivative of y=sin(x)-cos(x) ?
The first derivative of y=sin(x)-cos(x) is cos(x)+sin(x)