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Popular >

integral of (z+3)^4

Solution

\int (z + 3)^{4} d z

Solution

\frac{( z + 3 ) ^{5}}{5} + C

Solution steps

\int (z + 3)^{4} d z

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = z + 3

= \frac{( z + 3 ) ^{5}}{5}

Add a constant to the solution

= \frac{( z + 3 ) ^{5}}{5} + C

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\int_{- 1}^{1} 4 - 4 x^{2} d x

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xv'+v=((1+2v))/(1-v)

x v^{'} + v = \frac{( 1 + 2 v )}{1 - v}

Frequently Asked Questions (FAQ)

What is the integral of (z+3)^4 ?
The integral of (z+3)^4 is ((z+3)^5)/5+C