3^{5x}=27^{2x-4}

Lösung

3^{5 x} = 2 7^{2 x - 4}

x = 12

Schritte zur Lösung

3^{5 x} = 2 7^{2 x - 4}

Wende Exponentenregel an

5 x = 3 (2 x - 4)

Löse

5 x = 3 (2 x - 4) : x = 12

x = 12

2^{x + 3} = 16

\frac{75}{1 + 15 e ^{- 0.4 x}} = 25

7^{x^{2}} = (\frac{1}{49})^{3 x + 4}

5^{1 - 2 x} = 3^{x + 3}

e^{x^{2}} = e^{9}