7^{x^2}=(1/49)^{3x+4}

Lösung

7^{x^{2}} = (\frac{1}{49})^{3 x + 4}

x = - 2, x = - 4

Schritte zur Lösung

7^{x^{2}} = (\frac{1}{49})^{3 x + 4}

Wende Exponentenregel an

x^{2} = - 2 (3 x + 4)

Löse

x^{2} = - 2 (3 x + 4) : x = - 2, x = - 4

x = - 2, x = - 4

5^{1 - 2 x} = 3^{x + 3}

e^{x^{2}} = e^{9}

a^{x + 1} - a^{x} = 1

4^{x} - 9 \times 2^{x} + 8 = 0

so l v e f or x, 5^{2 x - 3} = 3^{3 x + 4}