sif(x)=x^2-1,g(x)=x^2+x

解

s i f (x) = x^{2} - 1, g (x) = x^{2} + x

s = 0, s \in R, s = 0, s \in R, x = - 1, x = - 1, x = 1, x = 1, f \in R f = 0 f \in R f = 0

解答ステップ

s i f (x) = x^{2} - 1

標準的な複素数形式で

s i f (x)

を書き換える:

0 + s f (x) i

0 + s f (x) i = x^{2} - 1

標準的な複素数形式で

x^{2} - 1

を書き換える:

(x^{2} - 1) + 0 i

0 + s f (x) i = (x^{2} - 1) + 0 i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[0 = x^{2} - 1 s f (x) = 0]

[0 = x^{2} - 1 s f (x) = 0] : s = 0, s \in R, s = 0, s \in R, x = - 1, x = - 1, x = 1, x = 1, f \in R f = 0 f \in R f = 0

s = 0, s \in R, s = 0, s \in R, x = - 1, x = - 1, x = 1, x = 1, f \in R f = 0 f \in R f = 0