What are the solutions to the equation (3x+3)^2=48 ?

The solutions to the equation (3x+3)^2=48 are x=(4-sqrt(3))/(sqrt(3)),x=-(4+sqrt(3))/(sqrt(3))

Find the zeros of (3x+3)^2=48

The zeros of (3x+3)^2=48 are x=(4-sqrt(3))/(sqrt(3)),x=-(4+sqrt(3))/(sqrt(3))

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(3 x + 3)^{2} = 48

x = \frac{4 - 3}{3}, x = - \frac{4 + 3}{3}

Decimal Notation

x = 1.30940 \dots, x = - 3.30940 \dots

Solution steps

(3 x + 3)^{2} = 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 3 = 48 : x = \frac{4 - 3}{3}

Solve

3 x + 3 = - 48 : x = - \frac{4 + 3}{3}

The solutions to the quadratic equation are:

x = \frac{4 - 3}{3}, x = - \frac{4 + 3}{3}

lo g_{\frac{1}{3}} (\frac{1}{27})

4 \cdot (2 \cdot x - 3) + (- x - 2) = 3

2 (3 x + 1) = 4 x + 2

x^{2} - 1 < 0.5

250 = 40 t - 0.8 t^{2}

What are the solutions to the equation (3x+3)^2=48 ?
The solutions to the equation (3x+3)^2=48 are x=(4-sqrt(3))/(sqrt(3)),x=-(4+sqrt(3))/(sqrt(3))
Find the zeros of (3x+3)^2=48
The zeros of (3x+3)^2=48 are x=(4-sqrt(3))/(sqrt(3)),x=-(4+sqrt(3))/(sqrt(3))