What are the solutions to the equation x^2-12x+9=0 ?

The solutions to the equation x^2-12x+9=0 are x=3(2+sqrt(3)),x=3(2-sqrt(3))

Find the zeros of x^2-12x+9=0

The zeros of x^2-12x+9=0 are x=3(2+sqrt(3)),x=3(2-sqrt(3))

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x^{2} - 12 x + 9 = 0

x = 3 (2 + 3), x = 3 (2 - 3)

Decimal Notation

x = 11.19615 \dots, x = 0.80384 \dots

Solution steps

x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 9 = 63

x_{1, 2} = \frac{- ( - 12 ) \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 3}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6 3}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6 3}{2 \cdot 1} : 3 (2 + 3)

x = \frac{- ( - 12 ) - 6 3}{2 \cdot 1} : 3 (2 - 3)

The solutions to the quadratic equation are:

x = 3 (2 + 3), x = 3 (2 - 3)

2 m^{2} - 11 m - 40 = 0

8 - m^{6}

49 x^{2} - 16

5 (x + 1) = 7 x + 6

x^{3} - 8 = 0

What are the solutions to the equation x^2-12x+9=0 ?
The solutions to the equation x^2-12x+9=0 are x=3(2+sqrt(3)),x=3(2-sqrt(3))
Find the zeros of x^2-12x+9=0
The zeros of x^2-12x+9=0 are x=3(2+sqrt(3)),x=3(2-sqrt(3))