What are the solutions to the equation 2m^2-11m-40=0 ?

The solutions to the equation 2m^2-11m-40=0 are m=8,m=-5/2

Find the zeros of 2m^2-11m-40=0

The zeros of 2m^2-11m-40=0 are m=8,m=-5/2

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2 m^{2} - 11 m - 40 = 0

m = 8, m = - \frac{5}{2}

Decimal Notation

m = 8, m = - 2.5

Solution steps

2 m^{2} - 11 m - 40 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 40) = 21

m_{1, 2} = \frac{- ( - 11 ) \pm 21}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 11 ) + 21}{2 \cdot 2}, m_{2} = \frac{- ( - 11 ) - 21}{2 \cdot 2}

m = \frac{- ( - 11 ) + 21}{2 \cdot 2} : 8

m = \frac{- ( - 11 ) - 21}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

m = 8, m = - \frac{5}{2}

8 - m^{6}

49 x^{2} - 16

5 (x + 1) = 7 x + 6

x^{3} - 8 = 0

6 \cdot 6 - 20 - 32 \cdot \frac{1}{4}

What are the solutions to the equation 2m^2-11m-40=0 ?
The solutions to the equation 2m^2-11m-40=0 are m=8,m=-5/2
Find the zeros of 2m^2-11m-40=0
The zeros of 2m^2-11m-40=0 are m=8,m=-5/2