What are the solutions to the equation y^2-10y=-22 ?

The solutions to the equation y^2-10y=-22 are y=5+sqrt(3),y=5-sqrt(3)

Find the zeros of y^2-10y=-22

The zeros of y^2-10y=-22 are y=5+sqrt(3),y=5-sqrt(3)

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y^{2} - 10 y = - 22

y = 5 + 3, y = 5 - 3

Solution steps

y^{2} - 10 y = - 22

Move

22

to the left side

y^{2} - 10 y + 22 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 22 = 23

y_{1, 2} = \frac{- ( - 10 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 3}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 3}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 3}{2 \cdot 1} : 5 + 3

y = \frac{- ( - 10 ) - 2 3}{2 \cdot 1} : 5 - 3

The solutions to the quadratic equation are:

y = 5 + 3, y = 5 - 3

(2 x + 5)^{2} - 7 (2 x + 5) - 30 = 0

e^{i}

x^{2} + 8 x y + 15 y^{2}

x^{2} = 3 x + 3

4 x^{2} + 11 x - 3 = 0

What are the solutions to the equation y^2-10y=-22 ?
The solutions to the equation y^2-10y=-22 are y=5+sqrt(3),y=5-sqrt(3)
Find the zeros of y^2-10y=-22
The zeros of y^2-10y=-22 are y=5+sqrt(3),y=5-sqrt(3)